{"id":2416,"date":"2023-04-25T14:40:10","date_gmt":"2023-04-25T05:40:10","guid":{"rendered":"https:\/\/arithmer.blog\/?p=2416"},"modified":"2023-05-18T10:28:53","modified_gmt":"2023-05-18T01:28:53","slug":"familiar-mathematics-how-to-find-e-pi-cos-exp-log-with-a-calculator","status":"publish","type":"post","link":"https:\/\/arithmer.blog\/blog\/familiar-mathematics-how-to-find-e-pi-cos-exp-log-with-a-calculator","title":{"rendered":"\u8eab\u8fd1\u306b\u3042\u308b\u6570\u5b66_ \u96fb\u5353\u3067e\u3001\u03c0\u3001cos(x)\u3001exp(x)\u3001log(x)\u3092\u6c42\u3081\u308b\u65b9\u6cd5"},"content":{"rendered":"\n

\u3053\u3093\u306b\u3061\u306f\u3002\u7814\u7a76\u958b\u767a\u672c\u90e8AI\u30a8\u30f3\u30b8\u30cb\u30a2\u306e\u5e73\u7530\u670b\u7fa9\u3068\u7533\u3057\u307e\u3059\u3002<\/p>\n\n\n\n

\u300c\u8eab\u8fd1\u306b\u6709\u308b\u6570\u5b66\u300d\u306e\u30c6\u30fc\u30de\u3067\u4f55\u304b\u66f8\u3044\u3066\u3068\u8a00\u308f\u308c\u305f\u306e\u3067\u81ea\u5206\u306e\u6614\u304b\u3089\u597d\u304d\u306a\u30c6\u30fc\u30de\u3001<\/p>\n\n\n\n

\u7c21\u5358\u306a\u6a5f\u80fd\u3057\u304b\u306a\u3044\u96fb\u5353\u3067\u300ce,\u03c0,cos(x),exp(x),log(x)\u3092\u6c42\u3081\u3066\u307f\u308b\u300d\u3068\u3044\u3046\u306e\u3092\u66f8\u3044\u3066\u307f\u307e\u3059\u3002<\/p>\n\n\n\n

\u30aa\u30a4\u30e9\u30fc\u6570\uff08\u03b3\uff09\u3082\u6c42\u3081\u305f\u3044\u306e\u3067\u3059\u304c\u3044\u3044\u65b9\u6cd5\u304c\u601d\u3044\u3064\u304b\u306a\u3044\u306e\u3067\u3001\u3069\u306a\u305f\u304b\u6559\u3048\u3066\u304f\u3060\u3055\u3044\u3002<\/p>\n\n\n\n

\u3053\u3053\u3067\u7c21\u5358\u306a\u6a5f\u80fd\u3057\u304b\u306a\u3044\u96fb\u5353\u3068\u3044\u3046\u306e\u306f\u6b21\u306e\u3088\u3046\u306a\u3082\u306e\u3092\u60f3\u5b9a\u3057\u3066\u3044\u307e\u3059\u3002<\/p>\n\n\n\n

1.\u56db\u5247\u6f14\u7b97\u3068\u30eb\u30fc\u30c8\u3001\u00b1\u30dc\u30bf\u30f3\u304c\u4f7f\u3048\u308b\u3002(\u00b1\u30dc\u30bf\u30f3\u306f\u2013==\u3067\u3082\u4ee3\u7528\u53ef\u80fd)<\/p>\n\n\n\n

2.\u95a2\u6570\u96fb\u5353\u3067\u306a\u3044\u3002<\/p>\n\n\n\n

3.\u30e1\u30e2\u30ea\u30fc\u6a5f\u80fd\u304c\u306a\u3044\u3002<\/p>\n\n\n\n

\u3053\u3053\u30672\u306f\u5f53\u7136\u3068\u3057\u30663\u3092\u60f3\u5b9a\u3059\u308b\u306e\u306f\u306a\u305c\u304b\u3068\u8a00\u3046\u3068\u3001\u30e1\u30e2\u30ea\u30fc\u6a5f\u80fd\u304c\u3042\u308b\u3068\u7d1a\u6570\u306e\u8a08\u7b97\u304c\u7c21\u5358\u306b\u3067\u304d\u3066\u3057\u307e\u3046\u306e\u3067\u3001$$\\exp(x) = 1 + x + \\frac{x^2}{2!} + \\frac{x^3}{3!} + \u2026$$\u306a\u3069\u306e\u8a08\u7b97\u304c\u7c21\u5358\u306b\u3067\u304d\u3066\u3057\u307e\u3046\u304b\u3089\u3067\u3059\u3002(log(<\/ins>x)<\/ins>\u306e\u8a08\u7b97\u306f\u53ce\u675f\u304c\u9045\u304f\u3066\u5927\u5909\u3067\u3059\u304c)<\/p>\n\n\n\n

\u3067\u306f\u4e00\u3064\u305a\u3064\u3084\u3063\u3066\u307f\u307e\u3057\u3087\u3046\u3002<\/p>\n\n\n\n

<\/a>e<\/h1>\n\n\n\n

\u81ea\u7136\u5bfe\u6570\u306e\u5e95\u300ee\u300f\u306f\u6570\u5b66\u3067\u975e\u5e38\u306b\u91cd\u8981\u306a\u6570\u5024\u3067\u3042\u308a\u3001\u9ad8\u6821\u6570\u5b66\u2162\u3067\u5b66\u3073\u307e\u3059\u3002\u81ea\u7136\u5bfe\u6570\u306e\u5e95\u306f\u3001e \u2252 2.71828\u3068\u7121\u9650\u306b\u7d9a\u304f\u5024\u3067\u3042\u308a\u3001\u5fae\u7a4d\u5206\u3084\u6307\u6570\u95a2\u6570\u3001\u5bfe\u6570\u95a2\u6570\u3001\u8907\u7d20\u6570\u306a\u3069\u306e\u6570\u5b66\u7684\u306a\u6982\u5ff5\u3084\u5fdc\u7528\u306b\u304a\u3044\u3066\u91cd\u8981\u306a\u5f79\u5272\u3092\u679c\u305f\u3057\u3066\u3044\u307e\u3059\u3002\u307e\u305f\u3001\u81ea\u7136\u5bfe\u6570\u306e\u5e95\u306f\u81ea\u7136\u73fe\u8c61\u3092\u8a18\u8ff0\u3059\u308b\u6570\u5b66\u7684\u306a\u5f0f\u306b\u3082\u73fe\u308c\u308b\u305f\u3081\u3001\u7269\u7406\u5b66\u3084\u5de5\u5b66\u306a\u3069\u3067\u3082\u3088\u304f\u4f7f\u308f\u308c\u3001\u7406\u7cfb\u306e\u4eba\u306b\u306f\u99b4\u67d3\u307f\u6df1\u3044\u3068\u601d\u3044\u307e\u3059\u3002<\/p>\n\n\n\n

e\u306e\u5b9a\u7fa9$$\\lim_{h \\to 0}(1+h)^{1\/h}$$\u3092\u4f7f\u7528\u3057\u307e\u3059\u3002<\/p>\n\n\n\n

\u3053\u3053\u3067$h = 1\/2^n$\u3068\u3059\u308b\u3068<\/p>\n\n\n\n

<\/p>\n\n\n\n

$$e= \\lim_{n \\to \\infty} (1+ 1 \/2^n)^{2^n} $$<\/p>\n\n\n\n

<\/p>\n\n\n\n

\u3064\u307e\u308an\u3092\u5341\u5206\u5927\u304d\u3044\u6570\u5b57\u3001\u4f8b\u3048\u307010\u3068\u3057\u3066<\/p>\n\n\n\n

    \n
  1. 1\u30922\u3067n\u56de\u5272\u308b<\/li>\n\n\n\n
  2. 1\u3092\u8db3\u3059<\/li>\n\n\n\n
  3. 2\u4e57(\u00d7=)\u3092n\u56de\u3059\u308b<\/li>\n<\/ol>\n\n\n\n

    \u3067\u6c42\u307e\u308a\u307e\u3059\u3002<\/p>\n\n\n\n

    n=10\u3068\u3057\u305f\u3068\u304d\u306e\u5024\u306f<\/p>\n\n\n\n

    2.71695571854\u3068\u306a\u308a\u307e\u3057\u305f\u3002<\/p>\n\n\n\n

    \u672c\u5f53\u306e\u5024\u306f2.718281828\u3067\u3059\u306e\u3067\u3001\u308f\u308a\u3068\u3044\u3044\u3067\u3059\u306d\u3002<\/p>\n\n\n\n

    \"\"<\/figure>\n\n\n\n

    <\/a>exp(x)<\/h1>\n\n\n\n

    \u81ea\u7136\u5bfe\u6570\u306e\u5e95e\u3068\u3068\u3082\u306b\u4f7f\u308f\u308c\u308b\u306e\u304c\u305d\u306e\u6307\u6570\u95a2\u6570exp(x)\u3067\u3059\u3002<\/p>\n\n\n\n

    \u3053\u3061\u3089\u3082\u9ad8\u6821\u6570\u5b66\u2162\u3067\u7fd2\u3044\u307e\u3059\u304c\u3001\u6587\u7cfb\u306e\u65b9\u3067\u3082\u7d71\u8a08\u306e\u5206\u91ce\u3092\u5b66\u3093\u3060\u65b9\u306f\u3001\u6b63\u898f\u5206\u5e03\u306a\u3069\u3067\u898b\u305f\u3053\u3068\u304c\u3042\u308b\u304b\u3068\u601d\u3044\u307e\u3059\u3002<\/p>\n\n\n\n

    \u3053\u3061\u3089\u3082e\u306e\u8a08\u7b97\u3068\u540c\u3058\u3067\u3001<\/p>\n\n\n\n

    <\/p>\n\n\n\n

    $$\\exp(x) =  \\lim_{n \\to \\infty} (1+x\/2^n)^{2^n}$$<\/p>\n\n\n\n

    <\/p>\n\n\n\n

    \u3092\u4f7f\u7528\u3057\u307e\u3059\u3002\u3064\u307e\u308a\u3001\u5341\u5206\u5927\u304d\u306an\u306b\u5bfe\u3057\u3066\u3001<\/p>\n\n\n\n

      \n
    1. x\u30922\u3067n\u56de\u5272\u308b<\/li>\n\n\n\n
    2. 1\u3092\u8db3\u3059<\/li>\n\n\n\n
    3. 2\u4e57(\u00d7=)\u3092n\u56de\u3059\u308b<\/li>\n<\/ol>\n\n\n\n

      \u3067\u6c42\u3081\u308b\u3053\u3068\u304c\u3067\u304d\u307e\u3059\u3002<\/p>\n\n\n\n

      <\/a>\u03c0<\/h1>\n\n\n\n

      \u5186\u5468\u7387\uff08\u03c0\uff09\u306f\u3001\u5186\u306e\u5468\u56f2\u306e\u9577\u3055\u3068\u76f4\u5f84\u306e\u6bd4\u3068\u3057\u3066\u5b9a\u7fa9\u3055\u308c\u308b\u5b9a\u6570\u3067\u3001\u6570\u5b66\u306b\u304a\u3044\u3066\u975e\u5e38\u306b\u91cd\u8981\u306a\u5f79\u5272\u3092\u6301\u3063\u3066\u3044\u307e\u3059\u3002\u5186\u5468\u7387\u306e\u5024\u306f\u3001\u7d043.1415926535\u2026\u3067\u3042\u308a\u3001e\u3068\u540c\u69d8\u306b\u7121\u9650\u306b\u7d9a\u304f\u5c0f\u6570\u3067\u3059\u3002<\/p>\n\n\n\n

      \u5186\u5468\u7387\u306f\u3001\u5e7e\u4f55\u5b66\u3084\u89e3\u6790\u5b66\u3001\u7d71\u8a08\u5b66\u3001\u7269\u7406\u5b66\u306a\u3069\u306e\u69d8\u3005\u306a\u5206\u91ce\u3067\u5229\u7528\u3055\u308c\u307e\u3059\u3002\u305f\u3068\u3048\u3070\u3001\u5186\u5468\u7387\u3092\u7528\u3044\u3066\u5186\u306e\u9762\u7a4d\u3092\u6c42\u3081\u305f\u308a\u3001\u5186\u67f1\u3084\u7403\u4f53\u306e\u4f53\u7a4d\u3092\u6c42\u3081\u305f\u308a\u3059\u308b\u3053\u3068\u304c\u3067\u304d\u307e\u3059\u3002<\/p>\n\n\n\n

      \u5186\u5468\u7387\u306f\u3001\u53e4\u4ee3\u304b\u3089\u591a\u304f\u306e\u4eba\u3005\u306b\u3088\u3063\u3066\u7814\u7a76\u3055\u308c\u3001\u8a08\u7b97\u3055\u308c\u3066\u304d\u307e\u3057\u305f\u3002<\/p>\n\n\n\n

      \u3053\u3053\u3067\u306f<\/p>\n\n\n\n

      \u300e\u03b8\u304c\u5c0f\u3055\u3044\u6642\u3001sin\u03b8 \u2252 \u03b8\u300f\u3092\u4f7f\u7528\u3057\u3001<\/ins><\/p>\n\n\n\n

      \u03c0\u306e\u8fd1\u4f3c\u5024\u3092\u6c42\u3081\u308b\u8a08\u7b97\u5f0f$\\pi \\approx 2^n\\sin(\\pi\/2^n)$\uff09\u3092\u7528\u3044\u3066\u8a08\u7b97\u3057\u307e\u3059\u3002<\/p>\n\n\n\n

      $m$\u3092\u5341\u5206\u5927\u304d\u3044\u81ea\u7136\u6570\u3068\u3057\u3066\u3001<\/p>\n\n\n\n

      $\\sin(\\pi\/2^m)$\u3092\u8a08\u7b97\u3057\u3001$2^m$\u3092\u639b\u3051\u3066\u6c42\u3081\u308b\u65b9\u91dd\u3067\u884c\u304d\u307e\u3059\u3002<\/p>\n\n\n\n

      \u3053\u308c\u3092\u8a08\u7b97\u3059\u308b\u306b\u306f\u3001\u534a\u89d2\u306e\u5b9a\u7406<\/p>\n\n\n\n

      $$\\cos^2(\\theta\/2) = (1 + \\cos\\theta)\/2$$<\/p>\n\n\n\n

      \u3092\u4f7f\u7528\u3057\u307e\u3059\u3001<\/p>\n\n\n\n

      \u3064\u307e\u308a<\/p>\n\n\n\n

      $c_1 = \\cos(\\pi\/2)=0$<\/p>\n\n\n\n

      $c_{n+1} = \\sqrt{(1 + c_n)\/2}$<\/p>\n\n\n\n

      \u3068\u6f38\u5316\u5f0f\u3067\u8a08\u7b97\u3057<\/p>\n\n\n\n

      $c_n = \\cos(\\pi\/2^n)$<\/p>\n\n\n\n

      $\\sin(\\pi\/2^m ) = \\sqrt{1-c_n^2}$<\/p>\n\n\n\n

      $\\pi \\approx \\sin(\\pi\/2^n) \\times 2^n$<\/p>\n\n\n\n

      \u3068$\\pi$\u304c\u6c42\u307e\u308a\u307e\u3059\u3002<\/p>\n\n\n\n

      \u5177\u4f53\u7684\u306a\u64cd\u4f5c\u306f\u4ee5\u4e0b\u306e\u3088\u3046\u306b\u306a\u308a\u307e\u3059<\/p>\n\n\n\n

        \n
      1. \u306f\u3058\u3081\u306b0\u3092\u5165\u529b<\/li>\n\n\n\n
      2. \u4ee5\u4e0b\u3092m\u56de\u7e70\u308a\u8fd4\u3059\n
          \n
        1. 1\u3092\u8db3\u3059<\/li>\n\n\n\n
        2. 2\u3067\u5272\u308b<\/li>\n\n\n\n
        3. \u30eb\u30fc\u30c8\u3092\u53d6\u308b<\/li>\n<\/ol>\n<\/li>\n\n\n\n
        4. 2\u3092m+1\u56de\u639b\u3051\u308b<\/li>\n<\/ol>\n\n\n\n

          \u8a08\u7b97\u3057\u305f\u6240\u3001<\/p>\n\n\n\n

          8\u56de\u30673.141513801\u3068\u7d50\u69cb\u901f\u304f\u03c0\u304c\u623b\u308a\u307e\u3059\u3002(\u6b63\u89e3\u306f3.141592653\u2026)<\/p>\n\n\n\n

          <\/a>cos(x)<\/h1>\n\n\n\n

          \u5148\u307b\u3069\u5186\u5468\u7387\u3092\u6c42\u3081\u308b\u969b\u306bcos\uff08\u30b3\u30b5\u30a4\u30f3\uff09\u3092\u4f7f\u7528\u3057\u305f\u306e\u3067\u3001\u6b21\u306f\u3053\u308c\u3092\u6c42\u3081\u3066\u307f\u305f\u3044\u3068\u601d\u3044\u307e\u3059\u3002\u4ed6\u306e\u4e09\u89d2\u95a2\u6570\u306b\u3064\u3044\u3066\u306f\u3001cos\u306e\u5024\u304b\u3089\u6c42\u3081\u308b\u3053\u3068\u304c\u3067\u304d\u307e\u3059\u3002<\/p>\n\n\n\n

          \u4eca\u56de\u306f\u4e8c\u500d\u89d2\u306e\u5b9a\u7406\u3001$\\cos(2\\theta) = 2 \\cos^2(\\theta) -1$\u3092\u4f7f\u7528\u3057\u307e\u3059\u3002<\/p>\n\n\n\n

          \u6c42\u3081\u305f\u3044x\u306b\u5bfe\u3057\u3066\u5341\u5206\u5927\u304d\u3044m\u306b\u3064\u3044\u3066$x\/2^m$\u3092\u8003\u3048\u307e\u3059\u3002<\/p>\n\n\n\n

          \u3053\u308c\u306b\u5bfe\u3057\u3066<\/p>\n\n\n\n

          $c_0 = \\cos(x\/2^m) \\approx 1 \u2013 1\/2\\times (x\/2^m)^2$<\/p>\n\n\n\n

          $c_{n+1} = 2c_n^2 -1$<\/p>\n\n\n\n

          \u3068\u6f38\u5316\u5f0f\u3067\u8a08\u7b97\u3059\u308b\u3068\u3002<\/p>\n\n\n\n

          $c_n = \\cos(x\/2^{m-n})$<\/p>\n\n\n\n

          $c_m = \\cos(x)$\u3068\u6c42\u307e\u308a\u307e\u3059\u3002<\/p>\n\n\n\n

          (\u5168\u3066\u306e\u8a08\u7b97\u304c\u30e1\u30e2\u30ea\u30fc\u6a5f\u80fd\u306a\u3057\u306e\u96fb\u5353\u3067\u3067\u304d\u308b\u3053\u3068\u3092\u3054\u78ba\u8a8d\u304f\u3060\u3055\u3044)<\/p>\n\n\n\n

          \u5177\u4f53\u7684\u306a\u8a08\u7b97\u306f\u4ee5\u4e0b\u306e\u901a\u308a\u306b\u306a\u308a\u307e\u3059\u3002<\/p>\n\n\n\n

          c[0]\u306e\u8a08\u7b97<\/p>\n\n\n\n

            \n
          1. x\u3092m\u56de2\u3067\u5272\u308b<\/li>\n\n\n\n
          2. 2\u4e57\u3059\u308b<\/li>\n\n\n\n
          3. 2\u3067\u5272\u308b<\/li>\n\n\n\n
          4. \u00b1\u3092\u62bc\u3059<\/li>\n\n\n\n
          5. 1\u3092\u8db3\u3059<\/li>\n<\/ol>\n\n\n\n

            cos(x) = c[m]\u306e\u8a08\u7b97<\/p>\n\n\n\n

              \n
            1. \u4ee5\u4e0b\u3092m\u56de\u7e70\u308a\u8fd4\u3059\n
                \n
              1. \u4e8c\u4e57\u3059\u308b<\/li>\n\n\n\n
              2. 2\u500d\u3059\u308b<\/li>\n\n\n\n
              3. 1\u3092\u5f15\u304f<\/li>\n<\/ol>\n<\/li>\n<\/ol>\n\n\n\n

                \u5b9f\u9a13\u7684\u306bm=5,x = \u03c0\/6\u3068\u3059\u308b\u3068<\/p>\n\n\n\n

                c[5] = 0.4999595\u3068\u306a\u308a\u3001\u3044\u3044\u7cbe\u5ea6\u3092\u51fa\u3057\u3066\u3044\u308b\u3053\u3068\u304c\u5206\u304b\u308a\u307e\u3059\u3002<\/p>\n\n\n\n

                <\/a>log(x)<\/h1>\n\n\n\n

                \u6700\u5f8c\u306b\u5bfe\u6570\u306b\u3064\u3044\u3066\u8a08\u7b97\u3057\u3066\u307f\u307e\u3057\u3087\u3046\u3002\u3053\u308c\u306f\u30b9\u30de\u30fc\u30c8\u306b\u8a08\u7b97\u3067\u304d\u307e\u3059\u3002<\/p>\n\n\n\n

                $a^x$\u306e\u5fae\u5206\u304c$\\log(a)a^x$\u3067\u3042\u308b\u3053\u3068\u3092\u4f7f\u3044\u307e\u3059\u3002<\/p>\n\n\n\n

                $x=0$\u3067\u306e\u5fae\u5206\u3092\u8003\u3048\u3066\u3001<\/p>\n\n\n\n

                <\/p>\n\n\n\n

                $$\\log(a)= \\lim_{h\\to 0} \\frac{a^h -1}{h}$$<\/p>\n\n\n\n

                <\/p>\n\n\n\n

                $h=1\/2^m$\u3068\u3059\u308b\u3068\u3002<\/p>\n\n\n\n

                \u5341\u5206\u5927\u304d\u306am\u306b\u5bfe\u3057\u3066<\/p>\n\n\n\n

                $$\\log(a) \\approx (a^{1\/2^m} -1 )2^m$$<\/p>\n\n\n\n

                \u3064\u307e\u308a\u3001\u30eb\u30fc\u30c8\u30dc\u30bf\u30f3\u3092m\u56de\u62bc\u3057\u30661\u3092\u5f15\u3044\u3066$2^m$\u3092\u639b\u3051\u308c\u3070\u3067\u304d\u307e\u3059\u3002<\/p>\n\n\n\n

                \u5177\u4f53\u7684\u306a\u64cd\u4f5c\u306f\u4ee5\u4e0b\u306e\u3088\u3046\u306b\u306a\u308a\u307e\u3059\u3002<\/p>\n\n\n\n

                  \n
                1. \u30eb\u30fc\u30c8\u30dc\u30bf\u30f3\u3092m\u56de\u62bc\u3059<\/li>\n\n\n\n
                2. 1\u3092\u5f15\u304f<\/li>\n\n\n\n
                3. 2\u3092m\u56de\u639b\u3051\u308b<\/li>\n<\/ol>\n\n\n\n

                  \u5b9f\u9a13\u7684\u306b\u5e38\u7528\u5bfe\u6570\u3068\u81ea\u7136\u5bfe\u6570\u306e\u5e95\u306e\u5909\u63db\u3067\u4f7f\u308f\u308c\u308b log(10)=2.3025850..\u3092\u8a08\u7b97\u3057\u3066\u307f\u307e\u3059\u3002<\/p>\n\n\n\n

                  m=10\u3068\u3059\u308b\u3068\u30012.305175852\u3068\u306a\u308a\u3001\u3044\u3044\u7cbe\u5ea6\u3092\u51fa\u3057\u3066\u3044\u308b\u3053\u3068\u304c\u5206\u304b\u308a\u307e\u3059\u3002<\/p>\n\n\n\n

                  \u3053\u306e\u3088\u3046\u306b\u3001\u30b7\u30f3\u30d7\u30eb\u306a\u96fb\u5353\u3060\u3051\u3067\u3082\u8a08\u7b97\u3059\u308b\u3053\u3068\u306f\u3067\u304d\u3001\u4e00\u5b9a\u7a0b\u5ea6\u306e\u7cbe\u5ea6\u3042\u308b\u6570\u5b57\u3092\u5c0e\u304f\u3053\u3068\u304c\u3067\u304d\u307e\u3057\u305f\u3002\u8907\u96d1\u306a\u8a08\u7b97\u5f0f\u3082\u3001\u5480\u56bc\u3057\u3066\u7c21\u7565\u5316\u3059\u308b\u3053\u3068\u304c\u3067\u304d\u307e\u3059\u3002\u3053\u308c\u304b\u3089\u3082\u3001\u7b97\u8853\uff08Arithmetic\uff09\u306e\u904b\u52d5\u304c\u3066\u3089\u3001\u3044\u308d\u3044\u308d\u3068\u8003\u3048\u3066\u307f\u305f\u3044\u3068\u601d\u3044\u307e\u3059\u3002<\/p>\n\n\n\n

                  \u6570\u5b66\u306e\u5b9a\u6570\u3084\u95a2\u6570\u306f\u3001\u9577\u3044\u6b74\u53f2\u306e\u4e2d\u3067\u8a08\u7b97\u3055\u308c\u3066\u304d\u307e\u3057\u305f\u3002\u305d\u306e\u904e\u7a0b\u306f\u975e\u5e38\u306b\u91cd\u8981\u3067\u3042\u308a\u3001\u81ea\u5206\u81ea\u8eab\u3067\u8a08\u7b97\u6cd5\u3092\u767a\u898b\u3057\u3001\u8a66\u3057\u3066\u307f\u308b\u3053\u3068\u3067\u3001\u6570\u5b66\u306e\u6b74\u53f2\u3092\u8ffd\u4f53\u9a13\u3059\u308b\u3053\u3068\u304c\u3067\u304d\u307e\u3059\u3002\u307e\u305f\u3001\u3053\u306e\u3088\u3046\u306a\u53d6\u308a\u7d44\u307f\u3092\u901a\u3058\u3066\u3001\u6570\u5b66\u306e\u9762\u767d\u3055\u3092\u518d\u767a\u898b\u3059\u308b\u3053\u3068\u304c\u3067\u304d\u308b\u3067\u3057\u3087\u3046\u3002\u3053\u306e\u8a18\u4e8b\u304c\u8aad\u8005\u306e\u7686\u69d8\u306b\u3068\u3063\u3066\u3001\u6570\u5b66\u306e\u697d\u3057\u307f\u306e\u65b0\u305f\u306a\u767a\u898b\u306e\u304d\u3063\u304b\u3051\u3068\u306a\u308c\u3070\u3001\u7b46\u8005\u3068\u3057\u3066\u3082\u5927\u5909\u3046\u308c\u3057\u304f\u601d\u3044\u307e\u3059\u3002<\/p>\n","protected":false},"excerpt":{"rendered":"

                  \u3053\u3093\u306b\u3061\u306f\u3002\u7814\u7a76\u958b\u767a\u672c\u90e8AI\u30a8\u30f3\u30b8\u30cb\u30a2\u306e\u5e73\u7530\u670b\u7fa9\u3068\u7533\u3057\u307e\u3059\u3002 \u300c\u8eab\u8fd1\u306b\u6709\u308b\u6570\u5b66\u300d\u306e\u30c6\u30fc\u30de\u3067\u4f55\u304b\u66f8\u3044\u3066\u3068\u8a00\u308f\u308c\u305f\u306e\u3067\u81ea\u5206\u306e\u6614\u304b\u3089\u597d\u304d\u306a\u30c6\u30fc\u30de\u3001 \u7c21\u5358\u306a\u6a5f\u80fd\u3057\u304b\u306a\u3044\u96fb\u5353\u3067\u300ce,\u03c0,cos(x),exp(x),log(x)\u3092\u6c42 … <\/p>\n","protected":false},"author":3,"featured_media":2425,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[3,132],"tags":[],"_links":{"self":[{"href":"https:\/\/arithmer.blog\/index.php?rest_route=\/wp\/v2\/posts\/2416"}],"collection":[{"href":"https:\/\/arithmer.blog\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/arithmer.blog\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/arithmer.blog\/index.php?rest_route=\/wp\/v2\/users\/3"}],"replies":[{"embeddable":true,"href":"https:\/\/arithmer.blog\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=2416"}],"version-history":[{"count":4,"href":"https:\/\/arithmer.blog\/index.php?rest_route=\/wp\/v2\/posts\/2416\/revisions"}],"predecessor-version":[{"id":2424,"href":"https:\/\/arithmer.blog\/index.php?rest_route=\/wp\/v2\/posts\/2416\/revisions\/2424"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/arithmer.blog\/index.php?rest_route=\/wp\/v2\/media\/2425"}],"wp:attachment":[{"href":"https:\/\/arithmer.blog\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=2416"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/arithmer.blog\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=2416"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/arithmer.blog\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=2416"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}